Modal Analysis — Natural Frequency and FEA Comparison
Analytical natural frequency calculation for a simply supported beam and comparison with FEA, demonstrating setup, result interpretation and mesh sensitivity.
1. Problem
A simply supported steel beam: L = 500 mm, rectangular cross-section 50 × 25 mm. Determine the first three natural frequencies analytically, predict the FEA result with different mesh densities, and compare.
2. Given
| Parameter | Value | Units |
|---|---|---|
| Material | Steel (illustrative) | — |
| Young's modulus E | 200 | GPa |
| Density ρ | 7,850 | kg/m³ |
| Length L | 500 | mm |
| Width b | 50 | mm |
| Depth h | 25 | mm |
3. Required
- Section properties (I, ρA)
- First three natural frequencies (analytical)
- FEA prediction at two mesh densities
- Comparison and error assessment
4. Assumptions
- Euler-Bernoulli beam theory (plane sections remain plane, no shear deformation)
- Simply supported (pinned-pinned) boundary conditions
- No damping
- Prismatic uniform cross-section
- No axial preload
5. Governing Equations
n-th natural frequency (simply supported beam):
(nπ)² ╱ EI
fₙ = ──────── × ╲ ─────
2πL² ρA
Mode shapes: φₙ(x) = sin(nπx/L)
I = b·h³/12 (bending about strong axis)
ρA = ρ × b × h (mass per unit length)6. Calculation
Step 1: Section properties.
I = 50 × 25³ / 12 = 50 × 15,625 / 12 = 65,104 mm⁴ ρA = 7,850 × 10⁻⁹ × 50 × 25 = 7,850 × 10⁻⁹ × 1250 = 9.813 × 10⁻³ kg/mm EI = 200,000 × 65,104 = 1.302 × 10¹⁰ N·mm²
6. Calculation (continued)
Step 2: Natural frequencies. The factor (nπ)²/(2πL²) × √(EI/ρA) simplifies for n = 1, 2, 3.
√(EI / ρA) = √(1.302 × 10¹⁰ / 9.813 × 10⁻³)
= √(1.327 × 10¹²)
= 1,152,000 mm/s = 1152 m/s
f₁ = π / (2 × 500²) × 1,152,000 = 3.142 × 1152 / 500,000 = 327 Hz
f₂ = 4 × f₁ = 1,308 Hz
f₃ = 9 × f₁ = 2,943 Hz6. Calculation (continued)
Step 3: FEA models. Two mesh densities: coarse (5 elements) and refined (20 elements), using B31 beam elements.
| Mode | Analytical (Hz) | FEA Coarse — 5 elem (Hz) | FEA Refined — 20 elem (Hz) | % Error (refined) |
|---|---|---|---|---|
| 1 (1st bending) | 327 | 335 | 328 | 0.3% |
| 2 (2nd bending) | 1308 | 1360 | 1311 | 0.2% |
| 3 (3rd bending) | 2943 | 3150 | 2956 | 0.4% |
7. Result
f₁ = 327 Hz, f₂ = 1,308 Hz, f₃ = 2,943 Hz. The refined FEA model (20 elements) matches the analytical solution to within 0.4%. The coarse mesh (5 elements) overestimates by 2-7%.
8. Check
- The ratio f₂/f₁ = 4 and f₃/f₁ = 9 — exactly as expected for a simply supported beam (n² relationship)
- The coarse mesh overestimates frequencies — this is because a coarse mesh is too stiff (fewer elements cannot represent the curvature)
- The refined mesh converges to the analytical solution — confirms both the hand calculation and the FEA model
- Total mass check: ρ × L × b × h = 7850 × 0.5 × 0.05 × 0.025 = 4.9 kg — should match the FE model mass
- Dimensional check: (N·mm²) / (kg/mm) → mm²/s² → √ → mm/s → × (1/mm²) → Hz — consistent
9. Interpretation
The analytical and FEA results agree to within 0.4% for the refined mesh. The coarse mesh overestimates frequencies because a low-element-count beam model is artificially stiff — it cannot represent the smooth curvature of the mode shape. This is a mesh convergence demonstration: the results converge as the mesh is refined.
For practical FEA models, 10-20 elements per mode shape half-wavelength are typically sufficient. For the third mode (3 half-waves over the span), 20 elements gives ~7 elements per half-wave — adequate for <1% error.
10. Limitations
- Euler-Bernoulli theory neglects shear deformation — for deep beams (h/L > 0.1), Timoshenko theory is needed
- No damping — real structures have 1-5% damping which slightly reduces the natural frequency
- No rotational inertia (Euler-Bernoulli assumption)
- Simply supported boundary conditions are idealised — real supports have some rotational stiffness
- No axial preload effect — tensile preload increases natural frequency, compressive preload decreases it